7x^-4/5+70x^1/5

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Solution for 7x^-4/5+70x^1/5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(70*x^1)/5+(7*x^-4)/5 = 0

(70*x)/5+(7*x^-4)/5 = 0

14*x+7/5*x^-4 = 0

7*x*(1/5*x^-5+2) = 0

1/5*x^-5 = -2 // : 1/5

x^-5 = -10

-5 < 0

1/(x^5) = -10 // * x^5

1 = -10*x^5 // : -10

-1/10 = x^5

x^5 = -1/10 // ^ 1/5

x = -(1/10)^(1/5)

7*x = 0

7*x = 0 // : 7

x = 0

x in { 0} 

x = -(1/10)^(1/5)

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